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The inverse of A = \pmatrix{ a & b \cr c & d} is A^{-1} = \displaystyle \frac{1}{ad-bc} \pmatrix{ d & -b \cr -c & a }
Remember that in general AB \ne BA
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This question appears in the following syllabi:

SyllabusModuleSectionTopicExam Year
AQA A-Level (UK - Pre-2017)FP4Matrix algebraThe basics-
AQA AS Further Maths 2017Pure MathsMatrix Determinants and InversesMatrix Equations-
AQA AS/A2 Further Maths 2017Pure MathsMatrix Determinants and InversesMatrix Equations-
CBSE XII (India)AlgebraMatricesTypes, zero, identity, symmetric and skew symmetric-
CCEA A-Level (NI)FP1Matrix algebraThe basics-
Edexcel A-Level (UK - Pre-2017)FP1Matrix algebraThe basics-
Edexcel AS Further Maths 2017Core Pure MathsMatricesMatrix Equations-
Edexcel AS/A2 Further Maths 2017Core Pure MathsMatricesMatrix Equations-
Methods (UK)M5Matrix algebraThe basics-
OCR A-Level (UK - Pre-2017)FP1Matrix algebraThe basics-
OCR AS Further Maths 2017Pure CoreDeterminants, Inverses and EquationsMatrix Equations-
OCR MEI AS Further Maths 2017Core Pure ADeterminants and InversesMatrix Equations-
OCR-MEI A-Level (UK - Pre-2017)FP1Matrix algebraThe basics-
Pre-Calculus (US)E2Matrix algebraThe basics-
Scottish Advanced HighersM3Matrix algebraThe basics-
Scottish (Highers + Advanced)AM3Matrix algebraThe basics-
Universal (all site questions)MMatrix algebraThe basics-
WJEC A-Level (Wales)FP1Matrix algebraThe basics-