Te gradient of a straight line is found by calculating \displaystyle \frac{rise}{step}
Summary/Background
Straight lines have equations of the form y=mx+c, where c is the "y-intercept", in other words the point where the line crosses the y-axis. m is the gradient of the line, which can be found from the graph by constructing a triangle as shown to the right and measuring the "rise" and the "step". The gradient is given by "rise" divided by "step"
Software/Applets used on this page
This question appears in the following syllabi:
Syllabus | Module | Section | Topic | Exam Year |
---|---|---|---|---|
AQA GCSE (9-1) Foundation (UK) | A: Graphs | A9: Plotting Straight-Line Graphs | Straight-Line Graphs | - |
CBSE IX (India) | Algebra | Polynomials | Constant, linear, quadratic and cubic | - |
CBSE XI (India) | Coordinate Geometry | Straight Lines | General equation of a line | - |
CIE IGCSE (9-1) Maths (0626 UK) | 5 Co-ordinate Geometry | B5.4 Equations of Straight Lines | Straight-Line Graphs | - |
Edexcel GCSE (9-1) Foundation (UK) | A: Graphs | A9: Plotting Straight-Line Graphs | Straight-Line Graphs | - |
GCSE Foundation (UK) | Algebra | Graphs | The straight line graph | - |
OCR GCSE (9-1) Foundation (UK) | 7: Graphs of Equations and Functions | 7.02a: Straight Line Graphs | Straight-Line Graphs | - |
Universal (all site questions) | G | Graphs | The straight line graph | - |